wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given the equilibrium constant values
(I) N2(g)+12O2(g)N2O(g); KC=2.7×1018
(II) N2O4(g)2NO(g); KC=4.6×103
(III) 12N2(g)+O2(g)NO2(g) KC4.1×109
Thus for the reaction,
2N2O(g)+3O2(g)2N2O4(g),KC is

A
5.46×107
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5.46×107
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.832×106
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.832×106
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Join BYJU'S Learning Program
CrossIcon