Given the equilibrium constant values (I)N2(g)+12O2(g)⇌N2O(g);KC=2.7×10−18 (II)N2O4(g)⇌2NO(g);KC=4.6×10−3 (III)12N2(g)+O2(g)⇌NO2(g)KC4.1×10−9
Thus for the reaction, 2N2O(g)+3O2(g)⇌2N2O4(g),KC is
A
5.46×107
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B
5.46×10−7
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C
1.832×10−6
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D
1.832×106
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Solution
The correct option is D1.832×106 (I)N2(g)+12O2(g)⇌N2O(g);KC=2.7×10−18 (II)N2O4(g)⇌2NO(g);KC=4.6×10−3 (III)12N2(g)+O2(g)⇌NO2(g)KC=4.1×10−9
Required equilibrium is obtained if we operate. 2N2O(g)+3O2(g)⇌2N2O4(g) Eq.(III)×4−Eq.(I)×2−Eq.(III)×2