Given the following reaction at equillibrium,
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); Δ H = - v e$
Some inert gas is added at constant pressure to the system. Predict which of the following facts will be affected?

N H_{3} (g)

is produced

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Less

N H_{3} (g)

is produced

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No effect on equllibrium

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K_{p}

of the reaction is decreased

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Solution

The correct option is B Less $N H_{3} (g)$ is produced
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); Δ H = - v e$
If an inert gas is added at a constant pressure, the reaction goes to that side where the number of moles increases. So reverse reaction takes place and less ammonia is produced.

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Similar questions

Given the following reaction at equilibrium $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$ . Some inert gas is added at constant volume. Predict which of the following facts will be affected?

Q. Given the following reaction at equilibrium:

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

. Some inert gas at constant pressure is added to the system. Which of the following is true?

Q. Given the following reaction at equilibrium,

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

Some inert gas at constant pressure is added to the system. Predict which of the following facts will be affected?

Q. Given the following reaction at equilibrium

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

. Some inert gas at constant pressure is added to the system. Predict which of the following facts will be affected :

Given the following reaction at equilibrium $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$ . Some inert gas is added at constant volume. Predict which of the following facts will be affected?

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Given the following reaction at equillibrium, N2(g)+3H2(g)⇌2NH3(g);ΔH=−ve Some inert gas is added at constant pressure to the system. Predict which of the following facts will be affected?

The correct option is B Less NH3(g) is produced N2(g)+3H2(g)⇌2NH3(g);ΔH=−ve If an inert gas is added at a constant pressure, the reaction goes to that side where the number of moles increases. So reverse reaction takes place and less ammonia is produced.

Given the following reaction at equillibrium,
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); Δ H = - v e$
Some inert gas is added at constant pressure to the system. Predict which of the following facts will be affected?

The correct option is B Less $N H_{3} (g)$ is produced
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); Δ H = - v e$
If an inert gas is added at a constant pressure, the reaction goes to that side where the number of moles increases. So reverse reaction takes place and less ammonia is produced.