Question

Given the following reactions involving $A,B,C$ and $D$.

(i) $C+B^{+}\to C^{+}+B$

(ii) $A^{+}+D\to$ No reaction

(iii) $C^{+}+A\to$ No reaction

(iv) $D+B^{+}\to D^{+}+B$

The correct arrangement of $A,B,C,D$ in order of their decreasing ability as a reducing agent?

• A. $D>A>C>B$
• B. $A>C>D>B$
• C. $C>A>B>D$
• D. $C>A>D>B$

Answer 1

The correct option is D $C>A>D>B$

Explanation:

Considering all four equations one by one.

In equation (1), reaction shows that the redox activity of element $C$ is more than that of element $B$. So from this reaction, the order of activity is $C>B$

In equation (2), reaction shows that the redox activity of element $A$ is more than that of element $D$. So from this reaction, the order of activity is $A>D$

In equation (3), reaction shows that the redox activity of element $C$ is more than that of element $A$. So from this reaction, the order of activity is $C>A$

In equation $\left(4\right)$, reaction shows that the redox activity of element $D$ is more than that of element $B$. So from this reaction, the order of activity is $D>B$

Hence the order will be

$C>A>D>B$

Option D is correct