Given the following two statements
(S1):(q∨p)→(p↔~q) is a tautology.
(S2):~q∧(~p↔q) is a fallacy. Then:
only (S1) is correct.
both (S1) and (S2) are correct.
only (S2) is correct
both (S1) and (S2) are not correct.
Explanation for the correct option:
(S1):(q∨p)→(p↔~q)
S1 is not correct
(S2):~q∧(~p↔q)
S2 is not correct.
Hence, option(D) is correct.
(p ∧∼q)∧(∼p ∧ q) is ___.