Given the graph of the function y=−2tan(3x),∀x∈R
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Solution
Given the graph of y=−2tan(3x)∀x∈R
We observe from the graph that the period of y=−2tan3x is π3.
Since we know that tanx is defined for x≠(2n+1)π2∀x∈Z.
Therfore −2tan3x will be defined for 3x≠(2n+1)π2,∀x∈Z. ⇒x≠(2n+1)π6,∀x∈Z.
Therfore the Domain of y=−2tan3x is R−{(2n+1)π6}∀n∈Z.