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Question

Given the graph of y=sec2x.
Select the correct statements.

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Solution

Given: y=sec2x
Now, to find the domain, range and the period of this function, let's use the graph of sec2x as shown:

Now, from the graph, sec2x is not defined for x=π4;π4;3π4,5π4

Hence, every odd multiple of π4

Domain: R(2n+1)π/4;nZ

Now, from the graph sec2x ranges from (,1][1,).

Or Range of sec2x:R(1,1)

Also, we know the period of secx is 2π
Hence, the period of sec2x will be 2π/2 or π

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