Given the load $= 10 N$ , Effort applied $= 10 N$ . Find mechanical advantage (MA), also find the type of lever.

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Solution

Step 1: Given data
Given the load applied $= 10 N$
Effort applied $= 10 N$
Step 2: Formula used
$M A (m e c h a n i c a l a d v a n t a g e) = \frac{L o a d}{E f f o r t}$

Step 3: Substituting the value of the load, and effort we get,
$M A = \frac{10 N}{10 N} M A = 1$
Since the mechanical advantage is equal to 1 hence it is a lever of order I.

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