Given the load $= 420 N$ , Effort applied $= 350 N$ . Find mechanical advantage (MA), also find the type of lever.

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Solution

Step 01: Given:
The load applied $= 420 N$
Effort applied $= 350 N$
Let MA is the mechanical advantage.
Step 02: Since we know:
$M A (m e c h a n i c a l a d v a n t a g e) = \frac{L o a d}{E f f o r t}$
Step 03: Calculation:
Substituting the value of the load, and effort we get:
$M A = \frac{420 N}{350 N} M A = 1.2$
Since the mechanical advantage is greater than 1 hence it is a lever of order II.

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