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Question

Given the magnitude of vector A to be 6 units. Find the component of A along the x-axis?


A

33

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B

33^i

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C

33

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D

33^i

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Solution

The correct option is C

33


Well normally I guess by now you know how to find component of a vector along a given vector i.e.

(Magnitude of vector)×(cosine of angle between the two vectors)

This takes care of everything

In this case

6×cos150=6×cos(90+60)

= -6sin60=6×32=33

Caution:- Component of a vector is scalar. I agree it's tough to understand and remember trigonometric

identities intuitively. Also component of a vector is just the measure of the shadow

Here the length of shadow is 6cos30=6×32=33 but this component is on -ve x-axis.

But since the question asks the component along the direction of +ve x-axis, so the component should be 33


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