Given the points $A (- 2, - 9)$ and $B (6, 1)$ , a point P bisects $A B$ . Find the coordinate of P.

(2, - 4)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2, 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1, 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(2, - 4)$
Let coordinates of $P$ is $(x, y)$ .

We know that,
Section Formula $\Rightarrow \frac{m x_{2} + n x_{1}}{m + n}, \frac{m y_{2} + n y_{1}}{m + n}$

By section formula:
$x = \frac{- 2 + 6}{1 + 1} = 2$

$y = \frac{- 9 + 1}{1 + 1} = - 4$ .

Hence coordinates of $P$ is $(2, - 4)$ .

Suggest Corrections

Similar questions

Q. Given the points

A (- 3, - 2)

and

B (6, 1)

, determine the coordinates of point P on directed line segment that partitions in the ratio

\frac{2}{1}

Q. If the point

P (1, 2)

lies on line segment joining the points

A (2, 4)

and

B (4, 8)

then find

\frac{A P}{A B}

If the coordinates of points A and B are (-2, -2) and (2, -4) respectively, find the coordinates of the point P such that AP = $\frac{3}{7}$ AB, where P lies on the line segment AB.

Q. If the point P(1,2) lies on the line segments joining the point A(2,4) and B(4,8), then find

\frac{A P}{A B}

Q. If the coordinates of points A and B are (−2, −2) and (2, −4) respectively, find the coordinates of the point P
such that

A P = \frac{3}{7} A B

, where P lies on the line segment AB. [CBSE 2015]

Join BYJU'S Learning Program

Given the points A(−2,−9) and B(6,1), a point P bisects AB. Find the coordinate of P.

The correct option is A (2,−4)Let coordinates of P is (x,y).We know that,Section Formula ⇒mx2+nx1m+n,my2+ny1m+nBy section formula:x=−2+61+1=2y=−9+11+1=−4.Hence coordinates of P is (2,−4).

Given the points $A (- 2, - 9)$ and $B (6, 1)$ , a point P bisects $A B$ . Find the coordinate of P.