Question

Given the polymers,

A = Nylon 6 ,6; B= Buna-S; C = Polytehene.

Arrange these in decreasing/increasing order of their intermolecular forces.

• A. $A>B>C$
• B. $B>C>A$
• C. $B<C<A$
• D. $C<A<B$

Answer 1

The correct option is C $B<C<A$

$\begin{array}{c}\text{Nylon}6,6\text{has hydrogen bonding}\\ \text{so high intermolecular forces.}\\ \text{Nylon}6,6>\text{polyethylene}>\text{Buna-s}\\ B<C<A\\ c\text{is correct option.}\end{array}$