Given the polymers (i) Nylon-6,6 (ii) Buna-S (iii) Polythene.

Arrange these in the increasing order of their intermolecular forces (Lower to higher)

(i)>(ii)>(iii)

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(ii)>(iii )>(i)

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(ii)<(iii)<(i)

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(iii)<(i)<(ii)

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Solution

The correct option is A (i)>(ii)>(iii)
Nylon-6,6 contains amide bonds. Therefore, the intermolecular forces of attraction are stronger.

In Buns-S, due to delocalisation of π-electrons intermolecular forces of attraction are more than polythene.

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Arrange the following polymers in increasing order of their intermolecular forces.

(i) Nylon 6, 6, Buna-S, Polythene.

(ii) Nylon 6, Neoprene, Polyvinyl chloride.

Given the polmers : A = Nylon ; B = Buna-S ; C=Polythene. Arrange these in increasing order of their intermolecular forces (lower to higher)

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A =

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