Given the quadratic equation ${(x + 2)}^{2} = 4$ , find the value of $x$ .

- 4

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- 2

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2

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8

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Solution

The correct option is A $- 4$
Given, $(x + 2)^{2} = 4$
$(x + 2)^{2} - 4 = 0$
$(x + 2)^{2} - 2^{2} = 0$
Applying the formula of $a^{2} - b^{2} = (a - b) (a + b)$ gives us
$[(x + 2 - 2)] [x + 2 + 2] = 0$
$(x) (x + 4) = 0$
Hence, $x = 0$ or $x = - 4$

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