Given the standard oxidation potentials-E0Fes-Fe2-aq- 0-44 VE0Fe2-aq-Fe3-aq - -0-77 VThe standard EMF of the given reaction will be- Fes - 2Fe3-aq - 3Fe2-aq

Δ G^0 = nFE^0 The standard oxidation potentials are nbsp; E^0_Fe(s)/Fe^2+(aq)= 0.44 V E^0_Fe^2+(aq)/Fe^3+(aq) = 0.77 V ∴ Fe(s) → Fe^2+(aq) + 2e^ ....... ( ...

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Byju's Answer

Standard XII

Chemistry

Oxidation and Reduction

Given the sta...

Question

Given the standard oxidation potentials:
$E_{F e (s) / F e^{2 +} (a q)}^{0} = 0.44 V$
$E_{F e^{2 +} (a q) / F e^{3 +} (a q)}^{0} = - 0.77 V$

The standard EMF of the given reaction will be:
$F e (s) + 2 F e^{3 +} (a q) \to 3 F e^{2 +} (a q)$

- 0.33 V

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0.33 V

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- 1.21 V

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1.21 V

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Solution

The correct option is D $1.21 V$
$Δ G^{0} = - n F E^{0}$

The standard oxidation potentials are
$E_{F e (s) / F e^{2 +} (a q)}^{0} = 0.44 V$
$E_{F e^{2 +} (a q) / F e^{3 +} (a q)}^{0} = - 0.77 V$
$∴$
$F e (s) \to F e^{2 +} (a q) + 2 e^{-} . . . . . . . (1); Δ G_{1}^{0} = - 2 F \times 0.44 F e^{2 +} (a q) \to F e^{3 +} (a q) + e^{-} . . . . . . . . (2); Δ G_{2}^{0} = + F \times 0.77$

Multiply equation (2) by 2 and reverse the reaction,
$2 F e^{3 +} (a q) + 2 e^{-} \to 2 F e^{2 +} (a q) . . . . . . (3); Δ G_{3}^{0} = - 2 F \times 0.77$

Adding equation (1) and (3), we get
$F e (s) + 2 F e^{3 +} (a q) \to 3 F e^{2 +} (a q) . . . . . . . . (4); Δ G_{4}^{0} = - 2 F \times E^{0}$

$Δ G_{4}^{0} = Δ G_{1}^{0} + Δ G_{3}^{0}$
$- 2 F \times E^{0} = - 2 F \times 0.44 + - 2 F \times 0.77$
$E^{0} = 0.44 + 0.77$
$E_{c e l l}^{0} = 1.21 V$

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Similar questions

Q. What will be the

E^{0}

value for the given half cell reaction?

F e^{3 +} (a q) + 3 e^{-} \to F e (s)

Given:

E^{0}

value for the half cell reaction,

F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q); E^{0} = 0.77 V

F e^{2 +} (a q) + 2 e^{-} \to F e (s); E^{0} = - 0.44 V

Q. For the cell

Z n (s) | Z n^{2 +} (a q) | | M^{x +} (a q) | M (s)

, different half cells and their standard electrode potentials are given below:

$M^{x +} (a q / M (s))$	$A u^{3 +} (a q) / A u (s)$	$A g^{+} / A g (s)$	$F e^{3 +} (a q) / F e^{2 +} (a q)$	$F e^{2 +} (a q) / F e (s)$
$E_{M^{x +} / M^{/ (V)}}^{o}$	$1.40$	$0.80$	$0.77$	$- 0.44$