Given the standard potential of the following at 25-C- MnO2 - Mn3- E- - 0-95 V Mn3- - Mn2- E- - 1-51 VThe standard potential of MnO2 - Mn2- is-

The correct option is C 1.23 V 2e^ + MnO_2 → nbsp;Mn^2+ ; E^⊖ = ? nbsp; Δ G = 2FE^⊖ nbsp;i. nbsp; e^ + MnO_2 → Mn ...

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Nernst Equation

Given the sta...

Question

Given the standard potential of the following at $25^{\circ} C$ . $M n O_{2} \to M n^{3 +}$ ; $E^{⊖} = 0.95 V$
$M n^{3 +} \to M n^{2 +}$ ; $E^{⊖} = 1.51 V$
The standard potential of $M n O_{2} \to M n^{2 +}$ is:

- 0.56 V

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- 2.46 V

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- 1.23 V

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1.23 V

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Solution

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25^{\circ} C

M n O_{2} \to M n^{3 +} E^{\circ} = 0.95 V

M n^{+ 3} \to M n^{2 +} E^{\circ} = 1.51 V

M n O_{2} \to M n^{2 +}

25^{\circ} C

M n O_{2} \to M n^{3 +} E^{\circ} = 0.95 V

M n^{+ 3} \to M n^{2 +} E^{\circ} = 1.51 V

M n O_{2} \to M n^{2 +}

M n O_{4}^{-} / M n O_{2}

M n O_{4}^{-} / M n^{2 +} = 1.51 V

M n O_{2} / M n^{2 +} = 1.23 V

M n O {_{4}}^{-} / M n O_{2}

E {^{o}}_{M n O {_{4}}^{-} / M n^{2 +}} = 1.51 V

E {^{o}}_{M n O_{2} / M n^{2 +}} = 1.23 V

E_{M n O_{4}^{-} | M n O_{2}}^{\circ}

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O

E^{\circ} = 1.51 V

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O

E^{\circ} = 1.23 V

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