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Byju's Answer
Standard XII
Chemistry
Gibb's Energy and Nernst Equation
#8203;Given t...
Question
Given the standard potentials E
o
(Cu
2-
/Cu ) and E
o
(Cu
-
/Cu) as 0.340 V and 0.522V respectively,the value of E
o
(Cu
2-
/Cu
-
) is
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Solution
Dear Student
As the electrode potential for the half cell reaction is :
C
u
2
-
+
2
e
-
→
C
u
E
o
=
0
.
34
V
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
(
1
)
A
s
t
h
e
E
o
i
s
i
n
t
e
n
s
i
v
e
p
r
o
p
e
r
t
y
,
h
e
n
c
e
∆
G
o
i
s
c
a
l
c
u
l
a
t
e
d
∆
G
o
=
-
n
F
E
o
∆
G
o
f
o
r
t
h
i
s
r
e
a
c
t
i
o
n
i
s
=
-
2
F
×
0
.
34
=
-
0
.
68
F
C
u
-
+
e
-
→
C
u
E
o
=
0
.
522
V
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
(
2
)
∆
G
o
f
o
r
t
h
i
s
r
e
a
c
t
i
o
n
i
s
=
-
1
F
×
0
.
522
=
-
0
.
522
F
Now the desired reaction is
C
u
2
-
+
e
-
→
C
u
-
∆
G
3
=
-
1
F
E
3
o
T
o
g
e
t
t
h
i
s
r
e
a
c
t
i
o
n
e
q
(
1
)
-
e
q
(
2
)
H
e
n
c
e
,
∆
G
o
3
=
∆
G
o
1
-
∆
G
o
2
-
F
E
3
o
=
-
0
.
68
F
+
0
.
522
F
E
3
o
=
0
.
68
-
0
.
522
=
0
.
158
V
So the electrode potential for the desired reaction is E(Cu
2-
/Cu
-
) = 0.158 V
Regards.
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Similar questions
Q.
Given the standard potentials
E
o
(
C
u
2
+
/
C
u
)
and
E
o
(
C
u
+
/
C
u
)
as
0.340
V and
0.522
V respectively, the value of
E
o
(
C
u
2
+
/
C
u
+
)
is:
Q.
C
u
+
is not stable and undergoes disproportionation.
E
o
for
C
u
+
disproportionation is :
(
E
o
C
u
2
+
/
C
u
+
=
+
0.153
V
,
E
o
C
u
+
/
C
u
=
0.53
V
)
Q.
C
u
+
ion is not stable in aqueous solution because of disproportionation reaction whose
E
o
is: (Given;
E
o
C
u
2
+
/
C
u
+
=
0.15
,
E
o
C
u
2
+
/
C
u
s
=
0.34
V
)
Q.
Given that the standard potential (
E
∘
) of
C
u
2
+
/
C
u
and
C
u
+
/
C
u
are
0.340
V
and
0.522
V
respectively. The
E
∘
of
C
u
2
+
/
C
u
+
is:
Q.
Given that the standard potential (
E
∘
) of
C
u
2
+
/
C
u
and
C
u
+
/
C
u
are
0.340
V
and
0.522
V
respectively. The
E
∘
of
C
u
2
+
/
C
u
+
is:
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