Given the standard reduction potentials-Zn 2- - Zn -0-74 V - Cl 2 - Cl -1-36 V - H - - 1 - 2 H 2-0 V and Fe 3- - Fe 2-0-77 VThe order of increasing strength as reducing agent isA- Cl - Fe 2- H 2- ZnB- Cl - Fe 2- Zn - H 2C- H 2- Zn - Fe 2- Cl -D- Zn - H 2- Fe 2- Cl -

The correct option is A Cl , Fe2+, H2, Zn Correct order is: Cl , Fe2+, H2, Zn ...

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Standard XII

Chemistry

Secondary Cells

Given the sta...

Question

Given the standard reduction potentials:

Zn²⁺/Zn = - 0.74 V, Cl₂/Cl^- = 1.36 V, H⁺/1/2H₂ = 0 V and Fe³⁺/Fe²⁺ = 0.77 V.
The order of increasing strength as reducing agent is

Cl^-, Fe²⁺, H_2,Zn

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Cl^-, Fe²⁺,Zn, H₂

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H₂, Zn, Fe²⁺, Cl^-

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Zn, H₂, Fe²⁺, Cl^-

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Solution

The correct option is A
Cl^-, Fe²⁺, H_2,Zn

Correct order is:

Cl^-, Fe²⁺, H_2,Zn

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