Given the universal set
U = ${- 7, - 3, - 1, 5, 6, 8, 9} a n d A = {x : x < 2}$ .
Find (A').

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Solution

Given the universal set
U = ${- 7, - 3, - 1, 5, 6, 8, 9}, A = {x : x < 2}$

$\Rightarrow A = {- 7, - 3, - 1}$

The complement of set A

$\Rightarrow A^{'} = {5, 6, 8, 9}$

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Given the universal set U = {−7,−3,−1,5,6,8,9} and A={x:x<2}. Find (A').

Given the universal set U = {−7,−3,−1,5,6,8,9},A={x:x<2} ⇒A={−7,−3,−1} The complement of set A ⇒A′={5,6,8,9}

Given the universal set
U = ${- 7, - 3, - 1, 5, 6, 8, 9} a n d A = {x : x < 2}$ .
Find (A').

Given the universal set
U = ${- 7, - 3, - 1, 5, 6, 8, 9}, A = {x : x < 2}$

$\Rightarrow A = {- 7, - 3, - 1}$

The complement of set A

$\Rightarrow A^{'} = {5, 6, 8, 9}$