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Question

Given the vectors u=[5,4] and v=[3,1],|2u3v|=

A
[19,11]
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B
482
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C
[19,13]
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D
241310
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E
265
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Solution

The correct option is B 482
Since the vectors u=[5,4] and v=[3,1], we calculate 2u3v as shown below:

2u3v=[2(5)3(3),2(4)3(1)]=[109,8+3]=[19,11]

Now the distance from the origin to the end of the vector |2u3v| is as follows:

(19)2+112=361+121=482

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