Given three reactions-Reaction 1 -A aq- An- aq-ne-E-2 VReaction 2-B aq- Bn- aq-ne-E-3 VReaction 3-Cn- aq-ne- C aq-E-4 VThe correct decreasing order of the tendency of the species A- B and C to get oxidised is-

For any reaction if E_cell gt;0, the forward reaction is spontaneous. If nbsp;E_cell lt;0, the backward reaction is spontaneous. For Reaction 1 : A (aq.) ...

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Standard XIII

Chemistry

Electrode Potential

Given three r...

Question

Given three reactions:
Reaction 1 :
$A (a q .) ⇌ A^{n +} (a q .) + n e^{-}$
$E^{\circ} = + 2 V$

Reaction 2:
$B (a q .) ⇌ B^{n +} (a q .) + n e^{-}$
$E^{\circ} = - 3 V$

Reaction 3:
$C^{n +} (a q .) + n e^{-} ⇌ C (a q .)$
$E^{\circ} = + 4 V$

The correct decreasing order of the tendency of the species A, B and C to get oxidised is:

A > B > C

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C > B > A

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A > C > B

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B > C > A

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Solution

The correct option is A $A > B > C$
For any reaction if $E_{c e l l} > 0$ , the forward reaction is spontaneous. If $E_{c e l l} < 0$ , the backward reaction is spontaneous.

For Reaction 1 :
$A (a q .) ⇌ A^{n +} (a q .) + n e^{-}$
$E^{\circ} = + 2 V$
Oxidation is spontaneous

Reaction 2:
$B (a q .) ⇌ B^{n +} (a q .) + n e^{-}$
$E^{\circ} = - 3 V$
Backward reaction i.e. reduction is spontaneous
Reaction 3:
$C^{n +} (a q .) + n e^{-} ⇌ C (a q .)$
$E^{\circ} = + 4 V$
Forward reaction i.e. reduction is spontaneous

So, tendency of A is the highest for oxidation.
Between reaction 2 and reaction 3:
In reaction 2, $E^{\circ}$ for backward reaction (reduction reaction) is $+ 3 V$ , whereas for reaction 3 $E^{\circ}$ for reduction is $+ 4 V$
So, C has the highest tendency to get reduced, and thus the least tendency to get oxidised.
Correct decreasing order is:
$A > B > C$

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Given three reactions: Reaction 1 : A (aq.)⇌An+ (aq.)+ne− E∘=+2 V Reaction 2: B (aq.)⇌Bn+ (aq.)+ne− E∘=−3 V Reaction 3: Cn+ (aq.)+ne−⇌C (aq.) E∘=+4 V The correct decreasing order of the tendency of the species A, B and C to get oxidised is: