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Byju's Answer
Standard XII
Mathematics
Applications of Cross Product
Given three u...
Question
Given three unit vectors
→
a
,
→
b
,
→
c
; no two of which collinear satisfying
→
a
×
(
→
b
×
→
c
)
=
1
2
→
b
. The angle between
→
a
and
→
b
is
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Solution
Given that,
→
a
×
(
→
b
×
→
c
)
=
→
b
2
(
→
a
×
→
c
)
→
b
−
(
→
a
×
→
b
)
→
c
=
→
b
2
⇒
→
a
×
→
b
=
0
→
a
⊥
→
b
θ
=
90
0
Then,
We get the angle between
→
a
and
→
b
is
90
0
.
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0
Similar questions
Q.
Let
→
a
,
→
b
,
→
c
are three unit vectors of which
→
b
and
→
c
are non parallel. Let the angle between
→
a
and
→
b
be
α
and that angle between
→
a
and
→
c
be
β
. If
→
a
×
(
→
b
×
→
c
)
=
1
2
→
b
, then
Q.
If
→
a
,
→
b
,
→
c
are three unit vectors,
→
a
×
(
→
b
×
→
c
)
=
1
2
→
b
,
then angle between a and c is
Q.
For two vectors
→
A
and
→
B
,
→
A
+
→
B
=
→
C
and
|
→
A
|
+
|
→
B
|
=
|
→
C
|
. The angle between two vectors is:
Q.
Two vectors
→
A
and
→
B
such that
→
A
+
→
B
=
→
C
and
|
→
A
|
+
|
→
B
|
=
|
→
C
|
. The angle between two vectors is
Q.
Unit vectors
→
a
,
→
b
,
→
c
are coplanar. A unit vector
→
d
is perpendicular to them. If
(
→
a
×
→
b
)
×
(
→
c
×
→
d
)
=
1
6
^
i
−
1
3
^
j
+
1
3
^
k
and the angle between
→
a
and
→
b
is
30
o
, then
→
c
is/are :
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