Given $△$ DEF $\sim$ $△$ ABC. If AB = 4 cm, BC = 2 cm, CA = 3 cm and EF = 4 cm, then the perimeter of $△$ DEF is

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Solution

The correct option is A 18
Given $△$ DEF $\sim$ $△$ ABC.

$\frac{A B}{D E} = \frac{A C}{D F} = \frac{B C}{E F}$

$\frac{4}{D E} = \frac{3}{D F} = \frac{2}{4} = \frac{1}{2}$

$D E$ = 8 cm, $D F$ = 6 cm

$P e r i m e t e r (△ D E F)$ = (8 + 6 + 4) cm = 18 cm

$P e r i m e t e r (△ D E F)$ = 18 cm

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