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Byju's Answer
Standard XII
Mathematics
Properties of Determinants
Given = |...
Question
Given
△
=
∣
∣ ∣
∣
−
1
2
+
3
i
5
−
4
i
2
−
3
i
8
1
+
i
5
+
4
i
1
−
i
3
∣
∣ ∣
∣
Without expanding prove that
△
is real.
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Solution
Take conjugate and then change rows into columns and columns into rows. This gives
¯
¯¯¯
¯
△
=
△
Hence
△
must be real.
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Similar questions
Q.
Solve
(
1
1
−
4
i
−
2
1
+
i
)
(
3
−
4
i
5
+
i
)
Q.
Reduce
(
1
1
−
4
i
−
2
1
+
i
)
(
3
−
4
i
5
+
i
)
to the standard form.
Q.
Expressing
A
as the sum of Hermitian and a Skew-Hermitian matrix, where,
A
=
⎡
⎢
⎣
2
+
3
i
2
5
−
3
−
i
7
3
−
i
3
−
2
i
i
2
+
i
⎤
⎥
⎦
be
A
=
⎡
⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢
⎣
2
−
1
2
+
i
2
m
+
k
i
−
1
2
−
i
2
7
3
2
−
1
4
−
i
3
2
+
1
2
⎤
⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥
⎦
+
⎡
⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢
⎣
3
i
5
2
−
i
2
n
+
p
i
−
5
2
−
i
2
0
3
2
−
1
−
i
−
3
2
i
⎤
⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥
⎦
.Find
m
+
k
+
n
+
p
?
Q.
Without expanding the determinant at any stage,
∣
∣ ∣ ∣
∣
−
5
3
+
5
i
3
2
−
4
i
3
−
5
i
8
4
+
5
i
3
2
+
4
i
4
−
5
i
9
∣
∣ ∣ ∣
∣
,
its value is
Q.
Prove that the value of the determinant
∣
∣ ∣ ∣ ∣ ∣
∣
−
7
5
+
3
i
2
3
−
4
i
5
−
3
i
8
4
+
5
i
2
3
+
4
i
4
−
5
i
9
∣
∣ ∣ ∣ ∣ ∣
∣
is real.
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