Given two complex number z1=5+(5√3)i and z2=2√3+2i, the argument of z1z2 in degree is
A
0
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B
30
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C
60
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D
90
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Solution
The correct option is A0 z1z2=5+(5√3)i2√3+2i
Rationalize =(5+5√3i)(2√3−2i)(2√3+2i)(2√3−2i) =10√3−10i+10i−10√3i243−4i2 =10√3+10√343+4=40√3×316=5√32 z1z2 is a real number ⇒arg(z1z2)=0
Alternative solution: z1=5+5√3i arez1=tan−1(5√35)=60o z2=2√3+2i argz2=tan−1(22/√3)=tan−1(√3)=60o arg(z1z2)=arg(z1)−arg(z2)=60o−60o=0