Given two independence events $A$ and $B$ such that $P (A) = 0.3$ and $P (B) = 0.6$ . Find
$P (A \cap B)$

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Solution

Given, $P (A) = 0.3$ and $P (B) = 0.6$

For Independant events

$P (A \cap B)$ $= P (A) P (B)$

$P (A \cap B) = 0.3 \times 0.6 = 0.18$

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