Question

Given two independence events $A$ and $B$ such that $P\left(A\right)=0.3$ and $P\left(B\right)=0.6$. Find

$P(A\cap B)$

Answer 1

Given, $P\left(A\right)=0.3$ and $P\left(B\right)=0.6$

For Independant events

$P(A\cap B)$$=P\left(A\right)P\left(B\right)$

$P(A\cap B)=0.3\times 0.6=0.18$