Question

Given two independence events $A$ and $B$ such that $P\left(A\right)=0.3$ and $P\left(B\right)=0.6$. Find

$P(\overline{A}\cap \overline{B})$

Answer 1

given that, $P\left(A\right)=0.3$$\Rightarrow$$P\left(\overline{A}\right)=0.7$

$P\left(B\right)=0.6$ $\Rightarrow$ $P\left(\overline{B}\right)=0.4$

For Independant events

$\Rightarrow$$P(\overline{A}\cap \overline{B})$$=P\left(\overline{A}\right)P\left(\overline{B}\right)$

$=0.7\times 0.4=0.28$