Given two independent events $A, B$ such that $P (A) = 0.3, P (B) = 0.6$ . Determine
$P (A a n d n o t B)$

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Solution

$∵ A$ and $B$ are independent events.
$∴ P (A a n d n o t B) = P (A) \times P (¯ B)$
$= 0.3 \times (1 - 0.6)$
$= 0.3 \times 0.4$
$= 0.12$

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