Given two independent events $A, B$ such that $P (A) = 0.3, P (B) = 0.6$ . Determine
$P (n o t A a n d B)$

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Solution

$∵ A$ and $B$ are independent events.
$∴ P (n o t A a n d B) = P (¯ A) \times P (B)$
$= (1 - 0.3) \times (0.6)$
$= 0.7 \times 0.6$
$= 0.42$

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