Given two mutually exclusive events A and B such that P(A) = 1/2 and P(B) = 1/3, find P (A or B).

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Solution

Given:
P(A) = 1/2 and P(B) = 1/3
For mutually exclusive events A and B, we have:
P(A or B) = P(A) + P(B)
$= \frac{1}{2} + \frac{1}{3} = \frac{3 + 2}{6} = \frac{5}{6}$
Hence, $P (A o r B) = \frac{5}{6}$

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Similar questions

Given two mutually exclusive events A and B such that $P (A) = \frac{1}{2}$ and $P (B) = \frac{1}{3}$ find P(A or B).

Given $P (A) = \frac{3}{5}, P (B) = \frac{1}{5}$ Find P(A or B), If A and B are mutually exclusive events.

P (A) = \frac{3}{5}

P (B) = \frac{1}{5}

P (A \cup B)

A

B

P (A) = \frac{3}{5}

P (B) = \frac{2}{7}

P (A \cup B)

P (A) = \frac{1}{2}, P (B) = p, P (A \cup B) = \frac{3}{5}

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