Question

Given two positive integers $x$ and $y$ with $x<y$. The percent that $x$ is less than $y$ is:

• A. $\frac{100(y-x)}{x}$
• B. $\frac{100(x-y)}{x}$
• C. $\frac{100(y-x)}{y}$
• D. $100(y-x)$

Answer 1

Answer: (C)

$\frac{100(y-x)}{y}$

From the given instruction that $x<y$

This means that $y$ is greater than $x$

So the percent by which $x$ is less than $y$ is

$\frac{(y-x)}{y}\times 100=\frac{100(y-x)}{y}$