Given: A={a,b,c} and B={1,2,3}
⇒A×B={(a,1),(a,2),(a,3),(b,1),(b,2),(b,3),(c,1),(c,2),(c,3)}
(i) R={(a,2),(a,3),(b,1),(c,3),(b,2)}
It can be seen easily, for all (x,y)∈R
⇒(x,y)∈A×B
∴R⊆A×B
Hence, R is a relation from A to B
(ii) S={(a,3),(b,1),(c,2),(2,a)}
Here (2,a)∈S but (2,a)∉A×B
So, S⊄A×B
∴S is not a relation from A to B
Hence, R is a relation but S is not from A to B