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Standard VI

Mathematics

Perimeter of a Triangle

Given two sti...

Question

Given two sticks $A B$ and $C D$ of length $A B = 16 c m$ and $C D = 12 c m$ . Using these sticks, make a kite. Find the perimeter of the kite whose shape is rhombus.

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Solution

Since the kite is a rhombus .
$∴ A O = O B = \frac{A B}{2} = 8 c m$
$c o = 00 = \frac{C D}{2} = 6 c m$
$A D^{2} = \sqrt{A D^{2} + O D^{2}} = 10$
Similarly, BD = BC = AC = 10
So perimeter of kite = 10 + 10 + 10 + 10
= 40 cm

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Given two sticks AB and CD of length AB=16 cm and CD=12 cm. Using these sticks, make a kite. Find the perimeter of the kite whose shape is rhombus.

Since the kite is a rhombus .∴AO=OB=AB2=8cmco=00=CD2=6cmAD2=√AD2+OD2=10Similarly, BD = BC = AC = 10So perimeter of kite = 10 + 10 + 10 + 10 = 40 cm

Given two sticks $A B$ and $C D$ of length $A B = 16 c m$ and $C D = 12 c m$ . Using these sticks, make a kite. Find the perimeter of the kite whose shape is rhombus.

Since the kite is a rhombus .
$∴ A O = O B = \frac{A B}{2} = 8 c m$
$c o = 00 = \frac{C D}{2} = 6 c m$
$A D^{2} = \sqrt{A D^{2} + O D^{2}} = 10$
Similarly, BD = BC = AC = 10
So perimeter of kite = 10 + 10 + 10 + 10
= 40 cm