Given two vectors are ^i−^j and ^i+2^j, then unit vector coplanar with the two vectors and perpendicular to first is
A
1√2(^i+^k)
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B
1√5(2^i+^j)
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C
±1√2(^i+^j)
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D
None of these
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Solution
The correct option is D±1√2(^i+^j) Let →a=^i−^j and →b=^i+2^j The required vector is along the vector →a×(→a×→b)=(→a.→b)→a−(→a.→a)→b =−(^i−^j)−2(^i+2^j) =−3^i−3^j Hence required vectors are given by ±(−3^i−3^j)√9+9=±1√2(^i+^j)