Given- A- - A cos- - - A sin- - A vector B- which is perpendicular to A- - is given by

The correct option is A B sin θ î B cos θ ĵ A⃗ =Acosθî +Asinθĵ Vector perpendicular to #160; A⃗ is given by adding #160; 3Π /2 to #1 ...

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Standard XII

Physics

Vector Addition

Given: A⃗ =...

Question

Given: $\to A = A cos θ^i + A sin θ^j$ . A vector $\to B$ , which is perpendicular to $\to A$ , is given by

B cos θ^i - B sin θ^j

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B sin θ^i - B cos θ^j

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B cos θ^i + B sin θ^j

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B sin θ^i + B cos θ^j

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Solution

The correct option is A $B sin θ^i - B cos θ^j$
$\to A = A cos θ^i + A sin θ^j$
Vector perpendicular to $\to A$ is given by adding $3 Π / 2$ to $θ$ .
$\to B = B cos (\frac{3 Π}{2} + θ)^i + B sin (\frac{3 Π}{2} + θ)^j$
$= + B sin θ^i + (- B cos θ^j)$
$\to B = B sin θ^i - B cos θ^j$
to vector to be perpendicular, $\to A . \to B = 0$ checking
$\to A . \to B = A B cos sin θ + (- A B) cos θ - sin θ$
$\to A . \to B = 0$
So,
$\to B = B sin θ^i - B cos θ^j$

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Similar questions

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Given: →A=Acosθ^i+Asinθ^j. A vector →B, which is perpendicular to →A , is given by

Given: $\to A = A cos θ^i + A sin θ^j$ . A vector $\to B$ , which is perpendicular to $\to A$ , is given by