The correct option is B False
We will check if the given 3 vectors are linearly dependent or not. If yes, then they are coplanar. Else not.
So
Let α=→a−2→b+3c
β=2→a+3→b−4→c
γ=−→b+2→c
So if α,β, and γ are linearly dependent then,
for α=x→β+y→γ
There should be values of x and y which are not simultaneously zero.
So let’s find out.
→a−2→b+3→c=x(−2→a+3→b−4→c)
+y(−→b+2→c)
Equating the coefficients of →a,→b and →c. We get
-2x + 0.y = 1 (equating coefficient of →a)
3x – y = -2 (equating coefficient of →b)
-4x + 2y = 3 (equating coefficient of →c)
Solving the system of equations, we get x=−12 y=12
These values satisfy all 3 equations and thus the system of equations is consistent and has a non-zero solution.
So α,β and γ are linearly dependent and hence coplanar.