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Question

Given: a,b and c are coplanar.
Vectors a2b+3c,2a+3b4c andb+2c are non-coplanar vectors.

A
True
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B
False
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Solution

The correct option is B False
We will check if the given 3 vectors are linearly dependent or not. If yes, then they are coplanar. Else not.
So
Let α=a2b+3c
β=2a+3b4c
γ=b+2c
So if α,β, and γ are linearly dependent then,
for α=xβ+yγ
There should be values of x and y which are not simultaneously zero.
So let’s find out.
a2b+3c=x(2a+3b4c)
+y(b+2c)
Equating the coefficients of a,b and c. We get
-2x + 0.y = 1 (equating coefficient of a)
3x – y = -2 (equating coefficient of b)
-4x + 2y = 3 (equating coefficient of c)
Solving the system of equations, we get x=12 y=12
These values satisfy all 3 equations and thus the system of equations is consistent and has a non-zero solution.
So α,β and γ are linearly dependent and hence coplanar.

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