Given p-3-2-4k- a- b-k- c-k- and P-xa-yb-zc- then x- y- z are respectively-

The correct option is B 1/2, 3/2, 5/2 #160;p⃗=xa⃗+yb⃗+zc⃗ ⇒ 3î+2ĵ+4k̂=x(î+ĵ)+y(ĵ+k̂)+z(î+k̂) ⇒ 3î+2ĵ+4k̂=(x+z)î+(x+y)ĵ+(y+z)k̂ On comparing ...

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Definition of Vector

Given p⃗=3î...

Question

Given $\to p = 3^i + 2^j + 4^k, \to a =^i +^j, \to b =^j +^k, \to c =^i +^k$ and $\to P = x \to a + y \to b + z \to c$ , then $x, y, z$ are respectively.

\frac{3}{2}, \frac{1}{2}, \frac{5}{2}

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\frac{1}{2}, \frac{3}{2}, \frac{5}{2}

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\frac{5}{2}, \frac{3}{2}, \frac{1}{2}

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\frac{1}{2}, \frac{5}{2}, \frac{3}{2}

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Solution

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Similar questions

\to a =^i + 2^j + 3^k

\to b = 2^i -^j +^k

\to c = 3^i + 2^j +^k

\to a \times (\to b \times \to c)

x \to a + y \to b + z \to c

x + y + z

\to a = 2^i +^j + 3^k

\to b = 3^i + 2^j +^k

\to c =^i -^j - 4^k

\to d =^i + 2^j -^k

(\to a \times \to b) \times (\to c \times \to d) =

\to a = 3^i + 2^j + 2^k, \to b = -^i + 3^j -^k, \to c =^i +^j +^k

\to a \times (\to b \times \to c)

(\to a \times \to b) \times \to c

\to a =^i +^j, \to b =^j +^k, \to c = α \to a + β \to b

^i - 2^j +^k, 3^i + 2^j -^k, \to c

\frac{α}{β} =

\to a =^i +^j +^k

\to b =^i -^j +^k

\to c =^i -^j -^k

\to v

\to a

\to b

\to c

\frac{2}{\sqrt{3}}

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