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Question

Given,
X(g)nY(g)
If degree of dissociation is α, then Kc of the reaction in a vessel of 1 litre is:

A
nαn1α
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B
nα1α
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C
(nα)n1+α
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D
(nα)n1α
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Solution

The correct option is D (nα)n1α
Given,
X(g)nY(g)
If degree of dissociation is α, then Kc of the reaction in a vessel of 1 litre is (nα)n1α.
Since total volume is 1 L, the number of moles is molar concentration.
Let 1 mole of X is present initially.
α moles of X will dissociate to form nα moles of Y.
(1α) moles of X will remain.
The equilibrium constant Kc=[Y]nX
Kc=[nα]n(1α)

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