Given $x y = 5$ and $(x + y) = 36$ , find the value of $x^{2} + y^{2}$

Open in App

Solution

Here, $(x + y) = 36$ and $x y = 5$

${(x + y)}^{2} = x^{2} + y^{2} - 2 x y$

$x^{2} + y^{2} = 36^{2} + 2 * 5$

$x^{2} + y^{2} = 1296 + 10$

$x^{2} + y^{2} = 1306$

Suggest Corrections

Similar questions

(x + y) = 13

x y = 22

x^{2} + y^{2}

x + y = 3, x y = 5

x^{2} + y^{2}

x = \frac{\sqrt{5} - 2}{\sqrt{5} + 2}

y = \frac{\sqrt{5} + 2}{\sqrt{5} - 2}

x^{2} + y^{2} + x y

x - y + z = 5

x^{2} + y^{2} + z^{2} = 49

z x - x y - y z

If x2+xy+x=12 and y2+xy+y=18 then find the value of x-y is

Join BYJU'S Learning Program