Question

Given $y=x\sin x,\frac{dy}{dx}=$

• A. $\cos x$
• B. $x\cos x+\sin x$
• C. $-x\cos x+\sin x$
• D. $\cos x+\sin x$

Answer 1

The correct option is B $x\cos x+\sin x$

Given that,

$y=x\sin x$

On differentiating

$\frac{dy}{dx}=x\cos x+\sin x$

Hence, the value of $\frac{dy}{dx}=x\cos x+\sin x$