Glassy bead is of

B_{2} O_{3} + N a B O_{2}

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N a B O_{2} + N a_{3} B O_{3}

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N a_{2} B_{4} O_{7} + B_{2} O_{3}

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S i O_{2} + B_{2} O_{3}

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Solution

The correct option is A $B_{2} O_{3} + N a B O_{2}$
If borax, $N a_{2} B_{4} O ., 10 H_{2} O$ is heated on the platinum loop, a transparent colourless glass like bead of sodium metaborate $(N a B O_{2})$ and boric anhydide $(B_{2} O_{3})$

$N a_{2} B_{4} O_{7} Δ \to 2 N a B O_{2} + B_{2} O_{3}$

So, glassy bead is of $B_{2} O_{3} + N a B O_{2}$
Hence, Option "A" is the correct answer.

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Similar questions

N a_{2} B_{4} O_{7} .10 H_{2} O H e a t - -- \to X + N a B O_{2} + H_{2} O

X + C r_{2} O_{3} H e a t - -- \to Y G r e e n c o l o u r

X

Y

$N a B O_{2} + C O_{2} \to A + B$ . A & B are as follows

N a_{2} B_{4} O_{7} Δ \to 2 N a B O_{2} + B_{2} O_{3}

B_{2} O_{3} + C u O \to C u (B O_{2})_{2}

C u (B O_{2})_{2}

B_{2} O_{3}

S i O_{2}

H_{3} B O_{3}

△ - \to

A + B . A & B

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