Glucose gives silver mirror with ammoniacal silver nitrate because it has:

aldehyde group

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

ester group

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ketone group

No worries! We‘ve got your back. Try BYJU‘S free classes today!

alcoholic silver nitrate

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C aldehyde group
Glucose gives silver mirror with ammoniacal silver nitrate because of presence of $- C H O$ group (aldehyde group) in the structure of glucose.
${C H}_{2} O H {(C H O H)}_{4} C H O + {A g}_{2} O ⟶ {C H}_{2} O H {(C H O H)}_{4} C O O H g l u c o n i c a c i d + 2 A g ↓ s i l v e r m i r r o r$

Suggest Corrections