Glucose $(C_{6} H_{12} O_{6})$ contains ______ percentage of carbon by weight.

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Solution

Definition of Percentage by weight
It is defined as the mass percent composition of an element in a compound.
It can be abbreviated as w/W %
$P e r c e n t a g e b y w e i g h t = {\frac{w e i g h t o f t h e e l e m e n t}{w e i g h t o f c o m p o u n d} x 100} %$
Percentage carbon by weight in glucose:
Let us calculate the mass of glucose= 6 x mass of C + 12 x mass of H + 6 x mass of O
= 6 x 12 + 12 x 1 + 6 x 16
= 180 g
Total mass of carbon = 6 x 12 = 72 g
Therefore the percentage carbon by weight in glucose is:
$P e r c e n t a g e b y w e i g h t = {\frac{w e i g h t o f c a r b o n}{w e i g h t o f g l u \cos e} x 100} % = {\frac{72}{180} x 100} % = 40 %$
Conclusion: Glucose $(C_{6} H_{12} O_{6})$ contains 40 percentage of carbon by weight.

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Glucose (C6H12O6) contains ______ percentage of carbon by weight.

Glucose $(C_{6} H_{12} O_{6})$ contains ______ percentage of carbon by weight.