Question

Glucose reacts with $C{H}_{3}OH$ in the presence of dry $HCl$ to give:

• A. methyl-$\alpha$-D-glucoside
• B. methyl-$\beta$-D-glucoside
• C. both $A$ & $B$
• D. none of these

Answer 1

Answer: (C)

both $A$ & $B$

Glucose reacts with methanol in presence of dry $HCl$ to form alpha and beta methyl glycosides.

$C_6{H}_{12}{O}_6+C{H}_{3}OH\to \underset{X}{\alpha -C_6{H}_{11}{O}_{6}C{H}_3}+\underset{Y}{\alpha -C_6{H}_{11}{O}_{6}C{H}_3}$