8
Question
Glucose, when heated with CH3OH, in presence of dry HCl gas, α−methyl glucosides and β−methyl glucosides are formed. This is because it contains:
Glucose, when heated with CH3OH, in presence of dry HCl gas, α−methyl glucosides and β−methyl glucosides are formed. This is because it contains:
Open in App
Solution
The correct option is C a ring structure
Glucose reacts with methanol, in presence of dry HCl, to form alpha and beta methyl glycosides.
C6H12O6+CH3OH→α−C6H11O6CH3X+β−C6H11O6CH3Y
Formation of alpha and beta methyl glycosides is due to the ring structure of glucose, as the methyl alcohol can attack the anomeric carbon in 2 ways, leading to these two configurations.
Glucose reacts with methanol, in presence of dry HCl, to form alpha and beta methyl glycosides.
C6H12O6+CH3OH→α−C6H11O6CH3X+β−C6H11O6CH3Y
Formation of alpha and beta methyl glycosides is due to the ring structure of glucose, as the methyl alcohol can attack the anomeric carbon in 2 ways, leading to these two configurations.
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
