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Question

Glucose when reduced with HI and red Phosphours gives:

A
n-hexane
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B
n-heptane
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C
n-pentane
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D
n-octane
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Solution

The correct option is A n-hexane

On prolonged heating with red P & HI, it forms n-Hexane, ​suggesting that all the six carbon atoms are linked in a straight chain.​


This confirms the presence of 6 carbon chain in glucose. Hence option (a) is correct.

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