Question

Glyceraldehyde 3- phosphate is oxidised to 1, 3- bisphosphoglyceric acid along with

• A. ATP synthesis
• B. Release of phosphate group
• C. Release of $H^{+}$ and $e^{-}$ for forming NADH
• D. Release of electrons for reducing $NA{D}^{+}$

Answer 1

The correct option is C Release of $H^{+}$ and $e^{-}$ for forming NADH

Sixth step of glycolysis

In the sixth step of glycolysis 2 molecules of glyceraldehyde-3-phosphate is oxidised and phosphorylated to form 2 molecules of 1,3-bisphosphoglyceric acid.

The two hydrogen atoms released from 2 molecules of glyceraldehyde 3 phosphate combines to form 2 NADH and 2 protons. There is a release of an electron.

This reaction is catalysed by the enzyme glyceraldehyde-3-phosphate dehydrogenase.

Final answer: Release of $H^{+}$ and $e^{-}$ for forming NADH