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Question

Gold and copper are as heavy as water by 19 and 9 times respectively. The ratio in which these two metals be mixed so that the mixture is 17 times as heavy as water is

A
2:3
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B
3:4
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C
3:2
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D
4:1
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Solution

The correct option is D 4:1
Let the mass of 1 volume unit of water be 1.
Then,
1 volume unit of gold has mass 19 and 1 volume unit of copper has mass 9.
Now let g be the volume of gold used and c be the volume of copper.
Then,
(19g+9c)/(g+c)=17
19g+9c=17g+17c
2g=8c
gc=82=41
Required ratio =4:1.

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