Gold and copper are as heavy as water by 19 and 9 times respectively. The ratio in which these two metals be mixed so that the mixture is 17 times as heavy as water is
A
2:3
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B
3:4
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C
3:2
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D
4:1
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Solution
The correct option is D4:1 Let the mass of 1 volume unit of water be 1. Then, 1 volume unit of gold has mass 19 and 1 volume unit of copper has mass 9. Now let g be the volume of gold used and c be the volume of copper. Then, (19g+9c)/(g+c)=17 19g+9c=17g+17c 2g=8c gc=82=41 ∴ Required ratio =4:1.