Gold (atomic radius $= 0.144 n m$ ) crystallizes in a face centered unit cell. What is the length of a side of the unit cell?

0.407

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0.288

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0.332

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0.432

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Solution

The correct option is D $0.407$
For FCC,
$a = 2 \sqrt{2} R$

$a = 2 \sqrt{2} \times 0.144$ nm

$a = 0.407$ nm

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Gold (atomic radius =0.144 nm) crystallizes in a face centered unit cell. What is the length of a side of the unit cell?

The correct option is D 0.407For FCC,a=2√2Ra=2√2×0.144 nma=0.407nm

Gold (atomic radius $= 0.144 n m$ ) crystallizes in a face centered unit cell. What is the length of a side of the unit cell?

The correct option is D $0.407$
For FCC,
$a = 2 \sqrt{2} R$

$a = 2 \sqrt{2} \times 0.144$ nm

$a = 0.407$ nm