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Question

# Gold crystallises in fcc centred cubic structure. If atomic mass of gold is 197 g mol−1, the mass of the unit cell of gold will be:

A
3.25×1023Kg
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B
6.5×1023Kg
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C
3.9×1024Kg
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D
1.3×1024Kg
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Solution

## The correct option is C 1.3×10−24KgAtomic mass of gold is 197 g/mol. 1 mole of gold weighs 197 g. 1 mole of gold contains 6.023×1023 atoms. Hence, 6.023×1023 atoms of gold weighs 197 g. 1 atom of gold weighs 197 g6.023×1023 atomsA fcc unit cell of gold contains 4 atoms.The mass of the unit cell of gold = mass of 4 atoms of gold =197 g6.023×1023 atoms×4 atoms=1.3×10−21 g.Convert the unit from g to Kg.The mass of the unit cell of gold =1.3×10−21 g×1 kg1000 g=1.3×10−24 Kg.

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